Equivalence of Definitions of Equivalent Division Ring Norms/Null Sequence Equivalent implies Open Unit Ball Equivalent

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Theorem

Let $R$ be a division ring.

Let $\norm {\, \cdot \,}_1: R \to \R_{\ge 0}$ and $\norm {\, \cdot \,}_2: R \to \R_{\ge 0}$ be norms on $R$.


Let $\norm {\, \cdot \,}_1$ and $\norm {\, \cdot \,}_2$ satisfy:

for all sequences $\sequence {x_n}$ in $R:\sequence {x_n}$ is a null sequence in $\norm {\, \cdot \,}_1 \iff \sequence {x_n}$ is a null sequence in $\norm {\, \cdot \,}_2$


Then $\forall x \in R$:

$\norm x_1 < 1 \iff \norm x_2 < 1$


Proof

Let $x \in R$.

Let $\sequence {x_n}$ be the sequence defined by: $\forall n: x_n = x^n$.


\(\ds \norm x_1 < 1 \quad\) \(\leadstoandfrom\) \(\ds \) $\sequence {x_n}$ is a null sequence in $\norm {\, \cdot \,}_1$ \(\quad\) Sequence of Powers of Number less than One in Normed Division Ring
\(\ds \) \(\leadstoandfrom\) \(\ds \) $\sequence {x_n}$ is a null sequence in $\norm {\, \cdot \,}_2$ \(\quad\) Assumption
\(\ds \) \(\leadstoandfrom\) \(\ds \) $\norm x_2 < 1$ \(\quad\) Sequence of Powers of Number less than One in Normed Division Ring

$\blacksquare$


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