Equivalence of Definitions of Equivalent Division Ring Norms/Open Unit Ball Equivalent implies Norm is Power of Other Norm/Lemma 2/Lemma 2.2
< Equivalence of Definitions of Equivalent Division Ring Norms | Open Unit Ball Equivalent implies Norm is Power of Other Norm | Lemma 2
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Theorem
Let $R$ be a division ring.
Let $\norm {\, \cdot \,}_1: R \to \R_{\ge 0}$ and $\norm {\, \cdot \,}_2: R \to \R_{\ge 0}$ be norms on $R$.
Let $\norm {\, \cdot \,}_1$ and $\norm {\, \cdot \,}_2$ satisfy:
- $\forall y \in R:\norm y_1 \lt 1 \iff \norm y_2 \lt 1$
Then:
- $\forall y \in R:\norm y_1 = 1 \iff \norm y_2 = 1$
Proof
By assumption:
- $\forall y \in R:\norm y_1 \ge 1 \iff \norm y_2 \ge 1$
By Lemma 1:
- $\forall y \in R:\norm y_1 \le 1 \iff \norm y_2 \le 1$
Hence $\forall y \in R$:
\(\ds \norm y_1 = 1\) | \(\leadstoandfrom\) | \(\ds \norm y_1 \le 1, \norm y_1 \ge 1\) | ||||||||||||
\(\ds \) | \(\leadstoandfrom\) | \(\ds \norm y_2 \le 1, \norm y_2 \ge 1\) | Lemma 1 and by assumption | |||||||||||
\(\ds \) | \(\leadstoandfrom\) | \(\ds \norm y_2 = 1\) |
$\blacksquare$