# Equivalence of Definitions of Real Exponential Function/Proof 2

## Contents

## Theorem

The following definitions of the exponential function are equivalent.

### Definition 1

The **exponential function** can be defined as a power series:

- $\exp x := \displaystyle \sum_{n \mathop = 0}^\infty \frac {x^n} {n!}$

### Definition 2

The **exponential function** can be defined as the following limit of a sequence:

- $\exp x := \displaystyle \lim_{n \mathop \to +\infty} \paren {1 + \frac x n}^n$

### Definition 3

Let $e$ denote Euler's number.

Let $f: \Q \to \R$ denote the real-valued function defined as:

- $f \left({ x }\right) = e^x$

That is, let $f \left({ x }\right)$ denote $e$ to the power of $x$, for rational $x$.

Then $\exp : \R \to \R$ is defined to be the unique continuous extension of $f$ to $\R$.

$\exp \left({ x }\right)$ is called the **exponential of $x$**.

### Definition 4

Consider the natural logarithm $\ln x$, which is defined on the open interval $\openint 0 {+\infty}$.

From Logarithm is Strictly Increasing:

- $\ln x$ is strictly increasing.

From Inverse of Strictly Monotone Function:

- the inverse of $\ln x$ always exists.

The inverse of the natural logarithm function is called the **exponential function**, which is denoted as $\exp$.

Thus for $x \in \R$, we have:

- $y = \exp x \iff x = \ln y$

### Definition 5

The **exponential function** can be defined as the unique solution $y = f \left({x}\right)$ to the first order ODE:

- $\dfrac {\d y} {\d x} = y$

satisfying the initial condition $f \left({0}\right) = 1$.

## Proof

From Derivative of Exponential Function and Exponential of Zero, each definition of $\exp$ satisfies the following:

- $ (1): \quad D_x \exp = \exp$
- $ (2): \quad \exp \left({ 0 }\right) = 1$

on $\R$.

From Exponential Function is Well-Defined, such a solution is unique.

Thus they all are all equivalent.

$\blacksquare$