Equivalence of Definitions of Weight of Topological Space

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Theorem

Let $T$ be a topological space.

Let $\mathbb B$ be the set of all bases of $T$.


The following definitions of the weight of $T$ are equivalent:

Definition 1

The weight of $T$ is defined as:

$\ds \map w T := \bigcap_{\BB \mathop \in \mathbb B} \card \BB$

where $\card \BB$ denotes the cardinality of $\BB$.

Definition 2

The weight of $T$ is the smallest cardinality of the elements of $\mathbb B$:

$\map w T := \min \set {\card \BB: \BB \in \mathbb B}$


Proof

By Class of All Cardinals is Subclass of Class of All Ordinals, the set:

$M = \set {\card \BB: \BB \in \mathbb B}$

is a subclass of the class of all ordinals.

By Class of All Ordinals is Well-Ordered by Subset Relation:

$M$ is well ordered by the $\subseteq$ relation.


By Class of All Ordinals is Well-Ordered by Subset Relation there exists a smallest element $m_0 \in M$:

$\forall m \in M: m_0 \subseteq m$

Hence by Smallest Element is Minimal there exists a basis $\BB_0$ of $T$ which has minimal cardinality:

$m_0 = \map {w_2} T$.

Let:

$\ds \map {w_1} T = \bigcap_{\BB \mathop \in \mathbb B} \card \BB$

By Intersection is Subset:

$\ds \map {w_1} T = \bigcap M \subseteq m_0$

But by Intersection is Largest Subset:

$\ds \mathfrak m_0 \subseteq \bigcap M$

By definition of set equality:

$\map {w_1} T = \map {w_2} T$

and hence the result.

$\blacksquare$


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