Euclidean Algorithm/Examples/24 and 138/Integer Combination
< Euclidean Algorithm | Examples | 24 and 138
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Examples of Use of Euclidean Algorithm
$6$ can be expressed as an integer combination of $24$ and $138$:
- $6 = 6 \times 24 - 1 \times 138$
Proof
From Euclidean Algorithm: $24$ and $138$ we have:
\(\text {(1)}: \quad\) | \(\ds 138\) | \(=\) | \(\ds 5 \times 24 + 18\) | |||||||||||
\(\text {(2)}: \quad\) | \(\ds 24\) | \(=\) | \(\ds 1 \times 18 + 6\) | |||||||||||
\(\text {(3)}: \quad\) | \(\ds 18\) | \(=\) | \(\ds 3 \times 6\) |
and so:
- $\gcd \set {24, 138} = 6$
Then we have:
\(\ds 6\) | \(=\) | \(\ds 24 - 1 \times 18\) | from $(2)$ | |||||||||||
\(\ds \) | \(=\) | \(\ds 24 - 1 \times \paren {138 - 5 \times 24}\) | from $(1)$ | |||||||||||
\(\ds \) | \(=\) | \(\ds 6 \times 24 - 1 \times 138\) | simplifying |
$\blacksquare$
Sources
- 1980: David M. Burton: Elementary Number Theory (revised ed.) ... (previous) ... (next): Chapter $2$: Divisibility Theory in the Integers: $2.3$ The Euclidean Algorithm: Problems $2.3$: $2 \ \text{(b)}$