Euclidean Space is Banach Space

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Let $m$ be a positive integer.

Then the Euclidean space $\R^m$, along with the Euclidean norm, forms a Banach space over $\R$.


The Euclidean space $\R^m$ is a vector space over $\R$.

That the norm axioms are satisfied is proven in Euclidean Space is Normed Space.

Then we have Euclidean Space is Complete Metric Space.

The result follows by the definition of a Banach space.