Excluded Point Space is Connected
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Theorem
Let $T = \left({S, \tau_{\bar p}}\right)$ be an excluded point space.
Then $T^*_{\bar p}$ is a connected space.
Proof 1
We have:
- Excluded Point Topology is Open Extension Topology of Discrete Topology
- Open Extension Space is Connected
$\blacksquare$
Proof 2
The only open set of $T$ which contains $p$ is $S$.
Therefore it is impossible to set up a separation of $T$, as $S$ will always need to be an element of such a separation.
$\blacksquare$
Proof 3
- Excluded Point Space is Ultraconnected
- Ultraconnected Space is Path-Connected
- Path-Connected Space is Connected
$\blacksquare$