Existence and Uniqueness of Sigma-Algebra Generated by Collection of Subsets
Theorem
Let $X$ be a set.
Let $\GG \subseteq \powerset X$ be a collection of subsets of $X$.
Then $\map \sigma \GG$, the $\sigma$-algebra generated by $\GG$, exists and is unique.
Proof
Existence
By Power Set is Sigma-Algebra, there is at least one $\sigma$-algebra containing $\GG$.
Next, let $\Bbb E$ be the collection of $\sigma$-algebras containing $\GG$:
- $\Bbb E := \set {\Sigma': \GG \subseteq \Sigma', \text{$\Sigma'$ is a $\sigma$-algebra} }$
By Intersection of Sigma-Algebras, $\Sigma := \bigcap \Bbb E$ is a $\sigma$-algebra.
Also, by Set Intersection Preserves Subsets:
- $\GG \subseteq \Sigma$
Now let $\Sigma'$ be a $\sigma$-algebra containing $\GG$.
By construction of $\Sigma$, and Intersection is Subset: General Result:
- $\Sigma \subseteq \Sigma'$
$\Box$
Uniqueness
Suppose both $\Sigma_1$ and $\Sigma_2$ are $\sigma$-algebras generated by $\GG$.
Then property $(2)$ for these $\sigma$-algebras implies both $\Sigma_1 \subseteq \Sigma_2$ and $\Sigma_2 \subseteq \Sigma_1$.
By definition of set equality:
- $\Sigma_1 = \Sigma_2$
$\blacksquare$
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Sources
- 2005: René L. Schilling: Measures, Integrals and Martingales ... (previous) ... (next): $3.4 \ \text{(ii)}$
- 2013: Donald L. Cohn: Measure Theory (2nd ed.) ... (previous) ... (next): $1.1$: Algebras and Sigma-Algebras