Fermat Number is not Perfect Power
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Theorem
There exist no Fermat numbers which are perfect powers.
Proof
Each Fermat number is in the form of $1 + 2^n$ for some $n \in \Z$.
This $n$ must also be a power of $2$.
From 1 plus Power of 2 is not Perfect Power except 9 we have:
- $1 + 2^n = a^b$
has only one solution $\tuple {n, a, b} = \tuple {3, 3, 2}$.
But $3$ is not a power of $2$.
Hence no Fermat numbers are perfect powers.
$\blacksquare$