First Order ODE/y' + y = 0

From ProofWiki
Jump to navigation Jump to search


The first order ODE:

$\dfrac {\d y} {\d x} + y = 0$

has the general solution:

$y = C e^{-x}$

where $C$ is an arbitrary constant.


This first order ODE is in the form:

$\dfrac {\d y} {\d x} + k y = 0$

where $k = 1$.

From First Order ODE: $\d y = k y \rd x$, this has the solution:

$y = C e^{-x}$