Four Fours/Lemmata/Two Fours/64/Solutions/2

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Puzzle: Two Fours: $64$

Using exactly $2$ instances of the number $4$, the task is to write an expression for $64$, using whatever arithmetical operations you consider necessary.


Solution

$64 = \sqrt {\paren {\sqrt {\sqrt 4} }^{4!} }$


Proof

$\sqrt {\paren {\sqrt {\sqrt 4} }^{4!} } = \sqrt {\sqrt {2^{24} } } = \sqrt {2^{12} } = \sqrt {4096} = 64$


Also presented as

Henry Ernest Dudeney's presentation of this (of which the above is a reproduction) is not the neatest.

This is how it appears according to Donald Ervin Knuth:

$64 = \surd \surd \surd \paren {4^{4!} }$


Sources