Four Straight Lines are Proportional iff Similar Parallelepipeds formed on them are Proportional
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Theorem
In the words of Euclid:
- If four straight lines be proportional, the parallelepipedal solids on them which are similar and similarly described will also be proportional; and if the parallelepipedal solids on them which are similar and similarly described be proportional, the straight lines will themselves also be proportional.
(The Elements: Book $\text{XI}$: Proposition $37$)
Proof
Let $AB$, $CD$, $EF$ and $GH$ be four straight lines in proportion, so that:
- $AB : CD = EF : GH$
Let similar and similarly situated parallelepipeds $KA$, $LC$, $ME$ and $NG$ be described on $AB$, $CD$, $EF$ and $GH$ respectively.
It is to be demonstrated that:
- $KA : LC = ME : NG$
- $KA : LC = AB^3 : CD^3$
For the same reason:
- $ME : NG = EF^3 : GH^3$
We have that:
- $AB : CD = EF : GH$
Therefore:
- $KA : LC = ME : NG$
$\Box$
Suppose that:
- $KA : LC = ME : NG$
- $KA : LC = AB^3 : CD^3$
For the same reason:
- $ME : NG = EF^3 : GH^3$
We have that:
- $KA : LC = ME : NG$
Therefore:
- $AB : CD = EF : GH$
$\blacksquare$
Historical Note
This proof is Proposition $37$ of Book $\text{XI}$ of Euclid's The Elements.
Sources
- 1926: Sir Thomas L. Heath: Euclid: The Thirteen Books of The Elements: Volume 3 (2nd ed.) ... (previous) ... (next): Book $\text{XI}$. Propositions