# Gaussian Isoperimetric Inequality

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## Theorem

Let $A$ be a measurable subset of $\R^n$ endowed with the standard Gaussian measure $\gamma^n$ with the density $\dfrac {\map \exp {-\norm x^2 / 2} } {\paren {2 \pi}^{n/2} }$

Denote by

- $A_\epsilon = \set {x \in \R^n : \map {\operatorname {dist} } {x, A} \le \epsilon}$

the $\epsilon$-extension of $A$.

The **Gaussian isoperimetric inequality** states that:

- $\displaystyle \liminf_{\epsilon \mathop \to +0} \epsilon^{-1} \set {\map {\gamma^n} {A_\epsilon} - \map {\gamma^n} A} \ge \map \varphi {\map {\Phi^{-1} } {\map {\gamma^n} A } }$

where:

- $\map \varphi t = \dfrac {\map \exp {-t^2 / 2} } {\sqrt {2 \pi} }$

and:

- $\map \Phi t = \displaystyle \int_{-\infty}^t \map \varphi s \rd s$

## Proof

## Source of Name

This entry was named for Carl Friedrich Gauss.