Henry Ernest Dudeney/Modern Puzzles/21 - Their Ages/Solution
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Modern Puzzles by Henry Ernest Dudeney: $21$
- Their Ages
- If you add the square of Tom's age to the age of Mary,
- the sum is $62$;
- but if you add the square of Mary's age to the age of Tom,
- the result is $176$.
- Can you say what are the ages of Tom and Mary?
Solution
Tom is $7$ and Mary is $13$.
Proof
Let $T$ be the age of Tom and $M$ be the age of Mary.
Expressing one variable in terms of another and eliminating one of them results in a quartic:
\(\ds T^2 + M\) | \(=\) | \(\ds 62\) | ||||||||||||
\(\ds M^2 + T\) | \(=\) | \(\ds 176\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds M\) | \(=\) | \(\ds 62 - T^2\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds \paren {62 - T^2}^2 + T\) | \(=\) | \(\ds 176\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds T^4 - 124 T^2 + T + 62^2 - 176\) | \(=\) | \(\ds 0\) |
Good luck with that.
So, let us assume that both $T$ and $M$ are natural numbers.
It is apparent that $T < 8$ and $M < 14$, otherwise the totals will be such that either $T$ or $M$ will be negative.
So:
- $176 - M^2 < 8$
which leads us to:
- $M^2 = 169$
giving us:
- $M = 13$
and:
- $T = 176 - 169 = 7$
We check the other equation:
- $7^2 + 13 = 49 + 13 = 62$
and all is well.
$\blacksquare$
Sources
- 1926: Henry Ernest Dudeney: Modern Puzzles ... (previous) ... (next): Solutions: $21$. -- Their Ages
- 1968: Henry Ernest Dudeney: 536 Puzzles & Curious Problems ... (previous) ... (next): Answers: $32$. Their Ages