Henry Ernest Dudeney/Modern Puzzles/41 - The Damaged Engine/Solution

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Modern Puzzles by Henry Ernest Dudeney: $41$

The Damaged Engine
We were going by train from Anglechester to Clinkerton, and an hour after starting some accident happened to the engine.
We had to continue the journey at $\tfrac 3 5$ of the former speed, and it made us $2$ hours late at Clinkerton,
and the driver said that if only the accident had happened $50$ miles farther on the train would have arrived $40$ minutes sooner.
Can you tell from that statement just how far it is from Anglechester to Clinkerton?


Solution

$200$ miles, of which the first $50$ miles were at $50$ miles per hour, and the rest at $30$ miles per hour.


Proof

Let $d$ miles be the distance from Anglechester to Clinkerton.

Let $v$ miles per hour be the speed of the train when working properly.

Let $d_1$ miles be the distance from Anglechester to where the train malfunctioned.

Let $t$ hours be the time the train would normally take to travel the journey.


We have:

\(\text {(1)}: \quad\) \(\ds d\) \(=\) \(\ds v t\)
\(\text {(1')}: \quad\) \(\ds d_1\) \(=\) \(\ds v\) an hour after starting some accident happened to the engine.
\(\text {(2)}: \quad\) \(\ds \dfrac {d_1} v + \dfrac {d - d_1} {v \times \tfrac 3 5}\) \(=\) \(\ds t + 2\) We had to continue ... $2$ hours late at Clinkerton
\(\text {(3)}: \quad\) \(\ds \dfrac {d_1 + 50} v + \dfrac {d - d_1 - 50} {v \times \tfrac 3 5}\) \(=\) \(\ds t + 1 \tfrac 1 3\) the driver said ... $40$ minutes sooner
\(\text {(4)}: \quad\) \(\ds \leadsto \ \ \) \(\ds 5 d - 2 d_1\) \(=\) \(\ds 3 v t + 6 v\) simplifying $(2)$
\(\text {(5)}: \quad\) \(\ds 5 d - 2 d_1 - 100\) \(=\) \(\ds 3 v t + 4 v\) simplifying $(3)$
\(\text {(6)}: \quad\) \(\ds \leadsto \ \ \) \(\ds 100\) \(=\) \(\ds 2 v\) $(4) - (5)$
\(\text {(7)}: \quad\) \(\ds \leadsto \ \ \) \(\ds 5 d - 2 d_1\) \(=\) \(\ds 150 t + 300\) substituting for $v$ in $(5)$ or $(6)$ and simplifying
\(\text {(8)}: \quad\) \(\ds \leadsto \ \ \) \(\ds 2 d - 2 d_1\) \(=\) \(\ds 300\) substituting for $t$ in $(7)$ and simplifying
\(\text {(9)}: \quad\) \(\ds \leadsto \ \ \) \(\ds 2 d - 100\) \(=\) \(\ds 300\) substituting for $d_1 = v$ in $(8)$
\(\text {(10)}: \quad\) \(\ds \leadsto \ \ \) \(\ds d\) \(=\) \(\ds 200\)

$\blacksquare$


Sources