Henry Ernest Dudeney/Puzzles and Curious Problems/169 - Shooting Blackbirds/Solution
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Puzzles and Curious Problems by Henry Ernest Dudeney: $169$
- Shooting Blackbirds
- Twice four and twenty blackbirds
- Were sitting in the rain;
- I shot and killed a seventh part,
- How many did remain?
Solution
- $4$.
Proof
The reader is initially tempted into thinking of:
- Twice four and twenty
as meaning:
- $2 \times 24$
and then is left scratching one's head at the absurdity of finding an integer solution to $x = \dfrac {48} 7$.
In fact:
- Twice four and twenty
is interpreted as:
- $\paren {2 \times 4} + 20$
which gives $28$.
Hence $\dfrac {28} 4 = 4$ were shot, leaving $24$ remaining.
But no! This is a trick puzzle.
The $24$ which were not shot flew away, leaving $4$ (dead) blackbirds remaining.
I hope Dudeney was pleased with himself.
$\blacksquare$
Sources
- 1932: Henry Ernest Dudeney: Puzzles and Curious Problems ... (previous) ... (next): Solutions: $169$. -- Shooting Blackbirds
- 1968: Henry Ernest Dudeney: 536 Puzzles & Curious Problems ... (previous) ... (next): Answers: $234$. Shooting Blackbirds