Hypothetical Syllogism/Formulation 3/Proof 2

Theorem

$\vdash \paren {\paren {p \implies q} \land \paren {q \implies r} } \implies \paren {p \implies r}$

Proof

We apply the Method of Truth Tables.

As can be seen by inspection, the truth values under the main connective is true for all boolean interpretations.

$\begin{array}{|ccccccc|c|ccc|} \hline ((p & \implies & q) & \land & (q & \implies & r)) & \implies & (p & \implies & r) \\ \hline F & T & F & T & F & T & F & T & F & T & F \\ F & T & F & T & F & T & T & T & F & T & T \\ F & T & T & T & T & F & F & T & F & T & F \\ F & T & T & T & T & T & T & T & F & T & T \\ T & F & F & F & F & T & F & T & T & F & F \\ T & F & F & T & F & T & T & T & T & T & T \\ T & T & T & F & T & F & F & T & T & F & F \\ T & T & T & T & T & T & T & T & T & T & T \\ \hline \end{array}$

$\blacksquare$

Sources

• 1971: Robert H. Kasriel: Undergraduate Topology ... (previous) ... (next): $\S1.2$: Some Remarks on the Use of the Connectives and, or, implies: Exercise $2$
• 1980: D.J. O'Connor and Betty Powell: Elementary Logic ... (previous) ... (next): $\S \text{I}: 7$: Determining the Truth Values of Complex Propositions
• 2008: David Joyner: Adventures in Group Theory (2nd ed.) ... (previous) ... (next): Chapter $1$: Elementary, my dear Watson: $\S 1.1$: You have a logical mind if...: Ponderable $1.1.4$