Induced Relation Generates Order Isomorphism
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Theorem
Let $\struct {A_1, \preceq_1}$ be an ordered set.
Let $\phi: A_1 \to A_2$ be a bijection.
Let:
- $\preceq_2 \mathop{:=} \set {\tuple {\map \phi x, \map \phi y}: x \in A_1 \land y \in A_1 \land x \mathop{\preceq_1} y}$
Then $\phi: \struct {A_1, \preceq_1} \to \struct {A_2, \preceq_2}$ is an order isomorphism.
Proof
Take any $x, y \in A_1$ such that $x \preceq_1 y$.
Since $x, y \in A_1$, it follows by the definition of a mapping that:
- $\map \phi x, \map \phi y \in A_2$
So $x \in A_1$ and $y \in A_1$ and $x \preceq_1 y$.
It follows from the definition of $\preceq_2$ that:
- $\map \phi x \preceq_2 \map \phi y$
Conversely, suppose that:
- $\map \phi x \preceq_2 \map \phi y$
By the definition of $\preceq_2$, it follows that:
- $x \preceq_1 y$
Therefore, the biconditional holds:
- $x \preceq_1 y \iff \map \phi x \preceq_2 \map \phi y$
By definition, it follows that:
- $\phi: \struct {A_1, \preceq_1} \to \struct {A_2, \preceq_2}$
is an order isomorphism.
$\blacksquare$
Sources
- 1971: Gaisi Takeuti and Wilson M. Zaring: Introduction to Axiomatic Set Theory: $\S 6.33$