Infinite Particular Point Space is not Weakly Countably Compact
Theorem
Let $T = \struct {S, \tau_p}$ be an infinite particular point space.
Then $T$ is not weakly countably compact.
Proof
By definition, $T$ is weakly countably compact if and only if every infinite subset of $S$ has a limit point in $S$.
Let $H \subseteq S$ be an infinite subset of $S$ where $p \notin H$.
$H$ is not open in $T$ by definition.
So from Subset of Particular Point Space is either Open or Closed, $H$ is closed in $T$.
Then we have that a Closed Set in Particular Point Space has no Limit Points.
The result follows from definition of weakly countably compact.
$\blacksquare$
If $T = \struct {S, \tau_p}$ is a finite particular point space, then Finite Space Satisfies All Compactness Properties applies.
Mistakes in Sources
See 1978: Lynn Arthur Steen and J. Arthur Seebach, Jr.: Counterexamples in Topology (2nd ed.): Part $\text {II}$: Counterexamples: $8 \text { - } 10$. Infinite Particular Point Topology: $12$ where it is stated that:
Particular Point Space is not Weakly Countably Compact
- [A particular point space] $X$ is not weakly countably compact since any set which does not contain $p$ has no limit points.
Sources
- 1978: Lynn Arthur Steen and J. Arthur Seebach, Jr.: Counterexamples in Topology (2nd ed.) ... (previous) ... (next): Part $\text {II}$: Counterexamples: $9 \text { - } 10$. Infinite Particular Point Topology: $12$