Ladies' Diary/Hour and Minute Hand in Straight Line

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Puzzle

"Being at so large a distance from the dial-plate of a great clock, that I could not distinguish the figures;
but as the hour and minute hands were very bright and glaring,"
the correspondent noted that they were in a straight line and pointing upwards to the right.
It was evening.
What was the time?


Solution

$5 \frac 5 {11}$ minutes, or approximately $5$ minutes and $27$ seconds, past $7$.


Proof

Let it be assumed from the description of the general direction of the hands, and the fact that it is evening, that it is some short time after $7$ p.m.

Thus the hour hand is pointing a little way past the $7$.

Hence the minute hand is pointing a little way past the $1$.


Let $x$ be the number of minutes after $7$ that it is.

Let $\theta$ be the angle made by the hands of the clock from the vertical at that time.


The minute hand rotates at $1$ revolution every $60$ minutes.

That is, $\dfrac {360 \degrees} {60} = 6 \degrees$ per minute.


The hour hand rotates at $1$ revolution every $12$ hours.

That is, $\dfrac {360 \degrees} {12 \times 60} = \dfrac 1 2 \degrees$ per minute.

But at $7$, the hour hand is already at $\dfrac {360 \degrees} {12} = 30 \degrees$ from the vertical.

Thus:

\(\ds \theta\) \(=\) \(\ds \dfrac x 2 + 30\) angle of hour hand
\(\ds \) \(=\) \(\ds 6 x\) angle of minute hand
\(\ds \leadsto \ \ \) \(\ds \dfrac {\paren {12 - 1} x} 2\) \(=\) \(\ds 30\)
\(\ds \leadsto \ \ \) \(\ds x\) \(=\) \(\ds \dfrac {60} {11}\)
\(\ds \) \(=\) \(\ds 5 \tfrac 5 {11}\)

So it is $5 \frac 5 {11}$ minutes past $7$.

$\dfrac 5 {11}$ minutes is $\dfrac {5 \times 60} {11}$ seconds, which evaluates to $27.\dot 2 \dot 7$ seconds.

$\blacksquare$


Sources