Laplace Transform of Derivative/Discontinuity at t = a

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Theorem

Let $f: \R \to \R$ or $\R \to \C$ be a continuous function, differentiable on any interval of the form $0 < t \le A$.

Let $f$ be of exponential order $a$.

Let $f'$ be piecewise continuous with one-sided limits on said intervals.

Let $\laptrans f$ denote the Laplace transform of $f$.


Let $f$ have a jump discontinuity at $t = a$.

Then:

$\laptrans {\map {f'} t} = s \laptrans {\map f t} - \map f 0 - e^{-a s} \paren {\map f {a^+} - \map f {a^-} }$


Proof

See Laplace Transform of Derivative with Finite Discontinuities and use $n = 1$ and $a_1 = a$.


Sources