# Leigh.Samphier/Sandbox/Inclusion Mapping on Normed Division Subring is Distance Preserving Monomorphism

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## Theorem

Let $\struct {R, \norm {\, \cdot \,} }$ be a normed division ring.

Let $\struct {S, \norm {\, \cdot \,}_S}$ be a normed division subring of $\struct {R, \norm {\, \cdot \,}}$.

Then the inclusion mapping $i : S \to R$ is a distance-preserving ring monomorphism.

## Proof

From Inclusion Mapping on Subring is Monomorphism, $i$ is a ring monomorphism.

Let $d$ be the metric induced by the norm $\norm {\, \cdot \,}$.

Let $d_S$ be the metric induced by the norm $\norm {\, \cdot \,}_S$.

Thus:

\(\, \ds \forall x, y \in S : \, \) | \(\ds \map d {\map i x, \map i y}\) | \(=\) | \(\ds \map d {x, y}\) | Definition of Inclusion Mapping | ||||||||||

\(\ds \) | \(=\) | \(\ds \norm {x - y}\) | Definition of Metric Induced by Norm on Division Ring | |||||||||||

\(\ds \) | \(=\) | \(\ds \norm {x - y}_S\) | Definition of Norm on Subring | |||||||||||

\(\ds \) | \(=\) | \(\ds \map {d_S} {x, y}\) | Definition of Metric Induced by Norm on Division Ring |

It follows that $i$ is distance-preserving by definition.

$\blacksquare$