Limit of Integer to Reciprocal Power/Proof 3
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Theorem
Let $\sequence {x_n}$ be the real sequence defined as $x_n = n^{1/n}$, using exponentiation.
Then $\sequence {x_n}$ converges with a limit of $1$.
Proof
Let $n^{1/n} = 1 + a_n$.
The strategy is to:
- $(1): \quad$ prove that $a_n > 0$ for $n > 1$
- $(2): \quad$ deduce that $n - 1 \ge \dfrac {n \paren {n - 1} } {2!} a_n^2$ for $n > 1$
and hence:
- $(3): \quad$ deduce that $0 \le a_n^2 \le \dfrac 2 n$
Let $n > 1$.
Then:
\(\ds n\) | \(=\) | \(\ds \paren {1 + a_n}^n\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 1 + n a_n + \dfrac {n \paren {n - 1} } {2!} a_n^2\) |
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Sources
- 1975: W.A. Sutherland: Introduction to Metric and Topological Spaces ... (previous) ... (next): $1$: Review of some real analysis: Exercise $1.5: 10$