Linear First Order ODE/dy = f(x) dx
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Theorem
Let $f: \R \to \R$ be an integrable real function.
- $(1): \quad \dfrac {\d y} {\d x} = \map f x$
has the general solution:
- $y = \ds \int \map f x \rd x + C$
where $\ds \int \map f x \rd x$ denotes the primitive of $f$.
Initial Condition
Consider the linear first order ODE:
- $(1): \quad \dfrac {\d y} {\d x} = \map f x$
subject to the initial condition:
- $y = y_0$ when $x = x_0$
$(1)$ has the particular solution:
- $y = y_0 + \ds \int_{x_0}^x \map f \xi \rd \xi$
where $\ds \int \map f x \rd x$ denotes the primitive of $f$.
Proof
\(\ds \dfrac {\d y} {\d x}\) | \(=\) | \(\ds \map f x\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds \int \d y\) | \(=\) | \(\ds \int \map f x \rd x\) | Solution to Separable Differential Equation | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds y\) | \(=\) | \(\ds \int \map f x \rd x\) | Primitive of Constant |
$\blacksquare$
Examples
Example: $y' = e^{-x^2}$
- $(1): \quad \dfrac {\d y} {\d x} = e^{-x^2}$
has the general solution:
- $y = \dfrac {\sqrt \pi} 2 \map {\erf} x + C$
where $\erf$ denotes the error function.
Sources
- 1958: G.E.H. Reuter: Elementary Differential Equations & Operators ... (previous) ... (next): Chapter $1$: Linear Differential Equations with Constant Coefficients: $\S 1$. The first order equation: $\S 1.1$ Introduction: $(2)$