# Locally Connected iff Components of Open Subsets are Open

## Theorem

Let $T = \left({S, \tau}\right)$ be a topological space.

Then $T$ is locally connected if and only if the connected components of open sets of $T$ are also open in $T$.

## Proof

### Necessary Condition

Follows directly from:

Open Subset of Locally Connected Space is Locally Connected
Component of Locally Connected Space is Open
Open Set in Open Subspace

$\blacksquare$