Lower Topology is Unique
Jump to navigation
Jump to search
Theorem
Let $T_1 = \left({S, \preceq, \tau_1}\right)$ and $T_2 = \left({S, \preceq, \tau_2}\right)$ be relational structures with lower topologies.
Then:
- $\tau_1 = \tau_2$
Proof
Define:
- $B := \left\{ {\complement_S \left({x^\succeq}\right): x \in S}\right\}$
where $x^\succeq$ denotes the upper closure of $x$.
Thus:
\(\ds \tau_1\) | \(=\) | \(\ds \tau \left({B}\right)\) | Definition of Topology Generated by Synthetic Sub-Basis | |||||||||||
\(\ds \) | \(=\) | \(\ds \tau_2\) | Definition of Topology Generated by Synthetic Sub-Basis |
$\blacksquare$
Sources
- 1980: G. Gierz, K.H. Hofmann, K. Keimel, J.D. Lawson, M.W. Mislove and D.S. Scott: A Compendium of Continuous Lattices
- Mizar article WAYBEL19:2