Measure Space has Exhausting Sequence of Finite Measure iff Cover by Sets of Finite Measure
Theorem
Let $\struct {X, \Sigma, \mu}$ be a measure space.
Then there exists an exhausting sequence $\sequence {E_n}_{n \mathop \in \N}$ in $\Sigma$ such that:
- $\forall n \in \N: \map \mu {E_n} < \infty$
if and only if there exists a sequence $\sequence {E_n}_{n \mathop \in \N}$ in $\Sigma$ such that:
- $(1): \quad \ds \bigcup_{n \mathop \in \N} E_n = X$
- $(2): \quad \forall n \in \N: \map \mu {E_n} < +\infty$
Proof
Necessary Condition
Suppose that there exists an exhausting sequence $\sequence {E_n}_{n \mathop \in \N}$ in $\Sigma$ such that:
- $\forall n \in \N: \map \mu {E_n} < \infty$
Let $\sequence {F_n}_{n \mathop \in \N}$ be an exhausting sequence in $\Sigma$ such that:
- $\forall n \in \N: \map \mu {F_n} < +\infty$
Then as $\sequence {F_n}_{n \mathop \in \N}$ is exhausting, have:
- $\ds \bigcup_{n \mathop \in \N} F_n = X$
It follows that the sequence $\sequence {F_n}_{n \mathop \in \N}$ satisfies $(1)$ and $(2)$.
$\Box$
Sufficient Condition
Let $\mu$ be any measure.
Let $\sequence {E_n}_{n \mathop \in \N}$ be a sequence satisfying $(1)$ and $(2)$.
Define $F_n := \ds \bigcup_{k \mathop = 1}^n E_k$.
Then by Sigma-Algebra Closed under Union:
- $F_n \in \Sigma$ for all $n \in \N$
Also, by Set is Subset of Union:
- $F_{n+1} = F_n \cup E_{n+1}$, hence $F_n \subseteq F_{n + 1}$
The definition of the $F_n$ assures that:
- $X = \ds \bigcup_{n \mathop \in \N} E_n = \bigcup_{n \mathop \in \N} F_n$
Hence $\sequence {F_n}_{n \mathop \in \N}$ is an exhausting sequence in $\Sigma$.
Furthermore, compute, for any $n \in \N$:
\(\ds \map \mu {F_n}\) | \(=\) | \(\ds \map \mu {\bigcup_{k \mathop = 1}^n E_k}\) | Definition of $F_n$ | |||||||||||
\(\ds \) | \(\le\) | \(\ds \sum_{k \mathop = 1}^n \map \mu {E_k}\) | Measure is Subadditive | |||||||||||
\(\ds \) | \(<\) | \(\ds +\infty\) | By $(2)$ |
Hence there exists an exhausting sequence $\sequence {E_n}_{n \mathop \in \N}$ in $\Sigma$ such that:
- $\forall n \in \N: \map \mu {E_n} < \infty$
$\blacksquare$
Sources
- 2005: René L. Schilling: Measures, Integrals and Martingales ... (previous) ... (next): $\S 4$: Problem $15$