Minimum of Exponential Random Variables has Exponential Distribution
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Theorem
Let $\beta_1, \beta_2, \ldots, \beta_n$ be positive real numbers.
Let $X_1, X_2, \ldots, X_n$ be independent random variables.
For each $i$, let $X_i \sim \Exponential {\beta_i}$, where $\Exponential {\beta_i}$ is the exponential distribution with parameter $\beta_i$.
Let:
- $\ds M = \map {\min_{1 \mathop \le i \mathop \le n} } {X_i} $
Then:
- $\ds M \sim \Exponential {\paren {\sum_{i \mathop = 1}^n \frac 1 {\beta_i} }^{-1} }$
Proof
We aim to show that:
- $\ds \map \Pr {M \le m} = 1 - \map \exp {-m \sum_{i \mathop = 1}^n \frac 1 {\beta_i} }$
for each $m > 0$.
Note that:
- $\ds M > m$
- $\ds X_i > m$
for each $i$.
We therefore have:
\(\ds \map \Pr {M > m}\) | \(=\) | \(\ds \map \Pr {\bigcap_{i \mathop = 1}^n \set {X_i > m} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \prod_{i \mathop = 1}^n \map \Pr {X_i > m}\) | Definition of Independent Random Variables | |||||||||||
\(\ds \) | \(=\) | \(\ds \prod_{i \mathop = 1}^n \map \exp {-\frac m {\beta_i} }\) | Definition of Exponential Distribution | |||||||||||
\(\ds \) | \(=\) | \(\ds \map \exp {-m \sum_{i \mathop = 1}^n \frac 1 {\beta_i} }\) | Exponential of Sum |
so:
- $\ds \map \Pr {M \le m} = 1 - \map \exp {-m \sum_{i \mathop = 1}^n \frac 1 {\beta_i} }$
$\blacksquare$