Multiplicative Inverse in Field is Unique

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Let $\struct {F, +, \times}$ be a field whose zero is $0_F$.

Let $a \in F$ such that $a \ne 0_F$.

Then the multiplicative inverse $a^{-1}$ of $a$ is unique.

Proof 1

From the definition of multiplicative inverse, $a^{-1}$ is the inverse element of the multiplicative group $\left({F^*, \times}\right)$.

The result follows from Inverse in Group is Unique.


Proof 2

From the definition of a field as a division ring, every element of $F^*$ is a unit.

The result follows from Product Inverse in Ring is Unique.