Natural Number is Superset of its Union

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Theorem

Let $n \in \N$ be a natural number as defined by the von Neumann construction.

Then:

$\bigcup n \subseteq n$


Proof

Let $n \in \N$.

From Natural Number is Transitive Set, $n$ is transitive.

From Class is Transitive iff Union is Subclass it follows directly that:

$\bigcup n \subseteq n$

$\blacksquare$


Sources