Heine-Borel Theorem/Real Line/Closed and Bounded Set

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Theorem

Let $F$ be a closed and bounded real set.

Let $C$ be a set of open real sets.

Let $C$ be a cover of $F$.


Then there is a finite subset of $C$ that covers $F$.


Proof

We are given that $C$ is a set of open real sets that covers $F$.

In other words, $C$ is an open cover of $F$.

We need to show that there is a finite subset of $C$ that covers $F$.

In other words, we need to show that $C$ has a finite subcover.


Let $F_o$ be the complement of $F$ in $\R$.

By definition of closed real set, $F_o$ is open as $F$ is closed.


Step 1: $C^*$ is an Open Cover of $\closedint a b$

It is demonstrated that $C^*$ is an open cover of $\closedint a b$.


Since $F$ is bounded, $F$ is contained in a closed and bounded interval $\closedint a b$ where $a, b \in \R$.

Define $C^* = C \cup \set {F_o}$.

Like $C$, $C^*$ is a set of open real sets as $F_o$ is open.


$C^*$ covers $F \cup F_o$ as $C$ covers $F$ and $\set {F_o}$ covers $F_o$.

$F_o \cup F$ equals $\R$ as $F_o$ is the complement of $F$ in $\R$.

So $C^*$ covers $\R$.

Furthermore, $C^*$ is an open cover of $\closedint a b$ as $\closedint a b$ is a subset of $\R$.


Step 2: $C^*$ has a Finite Subcover

It is demonstrated that $C^*$ has a finite subcover $C^*_f$.


$C^*$ is an open cover of the closed and bounded interval $\closedint a b$.

Therefore, by Open Cover of Closed and Bounded Real Interval has Finite Subcover, $C^*$ has a finite subcover $C^*_f$.


Step 3: $C$ has a Finite Subcover

It is demonstrated that $C$ has a finite subcover $C_f$.


Note that $F_o$ is the only element in $C^*$ that is not an element of $C$.

Therefore, $F_o$ is the only possible element in $C^*_f$ that is not an element of $C$ as $C^*_f$ is a subset of $C^*$.

This means that $C^*_f \setminus \set {F_o}$ is a subset of $C$.


Define $C_f = C^*_f \setminus \set {F_o}$.

According to the reasoning above, $C_f \subseteq C$.

Also, $C_f$ is finite as $C^*_f$ is finite.

What remains is to show that $C_f$ covers $F$.


We have:

\(\ds F\) \(\subseteq\) \(\ds \closedint a b\)
\(\, \ds \land \, \) \(\ds \closedint a b\) \(\subseteq\) \(\ds \bigcup_{O \mathop \in C^*_f} O\) as $C^*_f$ is a cover of $\closedint a b$
\(\ds \leadsto \ \ \) \(\ds F\) \(\subseteq\) \(\ds \bigcup_{O \mathop \in C^*_f} O\) Subset Relation is Transitive
\(\ds \leadsto \ \ \) \(\ds F \cap \relcomp \R {F_o}\) \(\subseteq\) \(\ds \paren {\bigcup_{O \mathop \in C^*_f} O} \cap \relcomp \R {F_o}\) Set Intersection Preserves Subsets
\(\ds \leadsto \ \ \) \(\ds F \cap \relcomp \R {\relcomp \R F}\) \(\subseteq\) \(\ds \paren {\bigcup_{O \mathop \in C^*_f} O} \cap \relcomp \R {F_o}\) as $F_o = \relcomp \R F$, the complement of $F$ in $\R$
\(\ds \leadsto \ \ \) \(\ds F \cap F\) \(\subseteq\) \(\ds \paren {\bigcup_{O \mathop \in C^*_f} O} \cap \relcomp \R {F_o}\) Relative Complement of Relative Complement
\(\ds \leadsto \ \ \) \(\ds F\) \(\subseteq\) \(\ds \paren {\bigcup_{O \mathop \in C^*_f} O} \cap \relcomp \R {F_o}\) Set Intersection is Idempotent
Furthermore, as $F \subseteq \closedint a b$:
\(\ds F\) \(\subseteq\) \(\ds \paren {\bigcup_{O \mathop \in C^*_f} O} \cap \relcomp \R {F_o}\)
\(\ds \) \(\subseteq\) \(\ds \paren {\bigcup_{O \mathop \in C^*_f \cup \set {F_o} } O} \cap \relcomp \R {F_o}\) by $\ds \paren {\bigcup_{O \mathop \in C^*_f} O} \subseteq \paren {\bigcup_{O \mathop \in C^*_f \cup \set {F_o} } O}$ and Set Intersection Preserves Subsets
\(\ds \) \(=\) \(\ds \paren {\bigcup_{O \mathop \in C^*_f \cup \set {F_o} } O} \setminus F_o\) Set Difference as Intersection with Complement
\(\ds \) \(=\) \(\ds \paren {\bigcup_{O \mathop \in \paren {C^*_f \setminus \set {F_o} \cup \set {F_o} } } O} \setminus F_o\) Set Difference Union Second Set is Union
\(\ds \) \(=\) \(\ds \paren {\paren {\bigcup_{O \mathop \in \paren {C^*_f \setminus \set {F_o} } } O} \cup F_o} \setminus F_o\)
\(\ds \) \(=\) \(\ds \paren {\bigcup_{O \mathop \in \paren {C^*_f \setminus \set {F_o} } } O} \setminus F_o\) Set Difference with Union is Set Difference
\(\ds \) \(\subseteq\) \(\ds \bigcup_{O \mathop \in \paren {C^*_f \setminus \set {F_o} } } O\) Set Difference is Subset
\(\ds \) \(=\) \(\ds \bigcup_{O \mathop \in C_f} O\) Definition of $C_f$

Thus, $C_f$ covers $F$.

This finishes the proof.

$\blacksquare$


Source of Name

This entry was named for Heinrich Eduard Heine and Émile Borel.


Sources