Permutation Induces Equivalence Relation/Corollary
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Theorem
Let $S_n$ denote the symmetric group on $n$ letters.
Let $\pi \in S_n$.
Let $\RR_\pi$ be the relation defined as:
- $i \mathrel {\RR_\pi} j \iff \exists k \in \Z: \map {\pi^k} i = j$
Then:
- $i \mathrel {\RR_\pi} j$ if and only if $i$ and $j$ are in the same cycle of $\pi$.
Proof
We have that Permutation Induces Equivalence Relation.
The equivalence classes of that equivalence relation are the cycles of $\pi$.
Hence the result by definition of equivalence class.
$\blacksquare$