Power Reduction Formulas/Hyperbolic Cosine Cubed/Proof 1

From ProofWiki
Jump to navigation Jump to search

Theorem

$\cosh^3 x = \dfrac {\cosh 3 x + 3 \cosh x} 4$


Proof

\(\ds \cosh 3 x\) \(=\) \(\ds 4 \cosh^3 x - 3 \cosh x\) Triple Angle Formula for Hyperbolic Cosine
\(\ds \leadsto \ \ \) \(\ds 4 \cosh^3 x\) \(=\) \(\ds \cosh 3 x + 3 \cosh x\) rearranging
\(\ds \leadsto \ \ \) \(\ds \cosh^3 x\) \(=\) \(\ds \dfrac {\cosh 3 x + 3 \cosh x} 4\) dividing both sides by $4$

$\blacksquare$