Power Reduction Formulas/Hyperbolic Cosine Cubed/Proof 3

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Theorem

$\cosh^3 x = \dfrac {\cosh 3 x + 3 \cosh x} 4$


Proof

\(\ds \cosh^3 x\) \(=\) \(\ds \cos^3 i x\) Hyperbolic Cosine in terms of Cosine
\(\ds \) \(=\) \(\ds \frac {\map \cos {3 i x} + 3 \cos i x} 4\) Cube of Cosine
\(\ds \) \(=\) \(\ds \frac {\cosh 3 x + 3 \cosh x} 4\) Hyperbolic Cosine in terms of Cosine

$\blacksquare$