# Power Set of Group under Induced Operation is Semigroup

## Theorem

Let $\struct {G, \circ}$ be a group.

Let $\struct {\powerset G, \circ_\mathcal P}$ be the algebraic structure consisting of the power set of $G$ and the operation induced on $\powerset G$ by $\circ$.

Then $\struct {\powerset G, \circ_\mathcal P}$ is a semigroup.

## Proof 1

We need to prove closure and associativity.

### Closure

Let $\struct {G, \circ}$ be a group, and let $A, B \subseteq G$.

\(\displaystyle \) | \(\) | \(\displaystyle \forall a \in A, b \in B: a \circ b \in G\) | |||||||||||

\(\displaystyle \) | \(\leadsto\) | \(\displaystyle A \circ B \subseteq G\) | Definition of Subset Product | ||||||||||

\(\displaystyle \) | \(\leadsto\) | \(\displaystyle A \circ B \in \powerset G\) | Definition of Power Set |

Thus $\struct {\powerset G, \circ_\mathcal P}$ is closed.

$\Box$

### Associativity

It follows from Subset Product within Semigroup is Associative that $\circ_\mathcal P$ is associative in $\struct {\powerset G, \circ_\mathcal P}$.

$\Box$

Thus $\struct {\powerset G, \circ_\mathcal P}$ is a semigroup.

$\blacksquare$

## Proof 2

By definition a group is also a semigroup.

The result then follows from Power Set of Semigroup under Induced Operation is Semigroup.

$\blacksquare$