Primitive of Cosine of a x over Power of p plus q of Sine of a x
Jump to navigation
Jump to search
Theorem
- $\ds \int \frac {\cos a x \rd x} {\paren {p + q \sin a x}^n} = \frac {-1} {a q \paren {n - 1} \paren {p + q \sin a x}^{n - 1} } + C$
Proof
\(\ds z\) | \(=\) | \(\ds p + q \sin a x\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds \frac {\d z} {\d x}\) | \(=\) | \(\ds a q \sin a x\) | Derivative of $\sin a x$ | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds \int \frac {\cos a x \rd x} {\paren {p + q \sin a x}^n}\) | \(=\) | \(\ds \int \frac {\d z} {a q z^n}\) | Integration by Substitution | ||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 {a q} \int z^{-n} \rd z\) | Primitive of Constant Multiple of Function | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 {a q} \frac {z^{-n + 1} } {-n + 1} + C\) | Primitive of Power | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac {-1} {a q \paren {n - 1} z^{n - 1} } + C\) | simplifying | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac {-1} {a q \paren {n - 1} \paren {p + q \sin a x}^{n - 1} } + C\) | substituting for $z$ |
$\blacksquare$
Also see
Sources
- 1968: Murray R. Spiegel: Mathematical Handbook of Formulas and Tables ... (previous) ... (next): $\S 14$: Integrals involving $\sin a x$ and $\cos a x$: $14.418$