Primitive of Reciprocal of q plus p by Secant of a x
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Theorem
- $\ds \int \frac {\d x} {q + p \sec a x} = \frac x q - \frac p q \int \frac {\d x} {p + q \cos a x} + C$
Proof
\(\ds \int \frac {\d x} {q + p \sec a x}\) | \(=\) | \(\ds \frac 1 q \int \frac {q \rd x} {q + p \sec a x}\) | multiplying top and bottom by $q$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 q \int \frac {\paren {q + p \sec a x - p \sec a x} \rd x} {q + p \sec a x}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 q \int \frac {\paren {q + p \sec a x} \rd x} {q + p \sec a x} - \frac p q \int \frac {\sec a x \rd x} {q + p \sec a x}\) | Linear Combination of Primitives | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 q \int \d x - \frac p q \int \frac {\sec a x \rd x} {q + p \sec a x}\) | simplifying | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac x q - \frac p q \int \frac {\sec a x \rd x} {q + p \sec a x} + C\) | Primitive of Constant | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac x q - \frac p q \int \frac {\cos a x \sec a x \rd x} {q \cos a x + p \cos a x \sec a x} + C\) | multiplying top and bottom by $\cos a x$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac x q - \frac p q \int \frac {\d x} {p + q \cos a x} + C\) | Secant is Reciprocal of Cosine |
$\blacksquare$
Also see
Sources
- 1968: Murray R. Spiegel: Mathematical Handbook of Formulas and Tables ... (previous) ... (next): $\S 14$: Integrals involving $\sec a x$: $14.459$