Product Formula for Norms on Non-zero Rationals

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Theorem

Let $\Q_{\ne 0}$ be the set of non-zero rational numbers.

Let $\Bbb P$ denote the set of prime numbers.

Let $a \in \Q_{\ne 0}$.


Then the following infinite product converges:

$\size a \times \ds \prod_{p \mathop \in \Bbb P}^{} \norm a_p = 1$

where:

$\size {\,\cdot\,}$ is the absolute value on $\Q$
$\norm {\,\cdot\,}_p$ is the $p$-adic norm on $\Q$ for prime number $p$


Proof

Lemma

Let $z \in \Z_{\ne 0}$.


Then the following infinite product converges:

$\size z \times \ds \prod_{p \mathop \in \Bbb P}^{} \norm z_p = 1$

$\Box$


Let $a = \dfrac b c$, where $b, c \in \Z_{\ne 0}$.

From the Lemma, the following infinite products converge:

$\size b \ds \times \prod_{p \mathop \in \Bbb P} \norm b_p = 1$
$\size c \ds \times \prod_{p \mathop \in \Bbb P} \norm c_p = 1$

From Quotient Rule for Real Sequences, the following infinite product converges:

$\ds \dfrac {\size b} {\size c} \times \prod_{p \mathop \in \Bbb P } \dfrac {\norm b_p} {\norm c_p} = \dfrac 1 1 = 1 $


We have:

\(\ds \size a \times \mathop \prod_{p \mathop \in \Bbb P} \norm a_p\) \(=\) \(\ds \size {\dfrac b c} \times \prod_{p \mathop \in \Bbb P} \norm {\dfrac b c}_p\)
\(\ds \) \(=\) \(\ds \dfrac {\size b} {\size c} \times \prod_{p \mathop \in \Bbb P} \dfrac {\norm b_p} {\norm c_p}\) Norm of Quotient
\(\ds \) \(=\) \(\ds 1\)

$\blacksquare$


Sources