Product of Indices of Real Number/Rational Numbers
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Theorem
Let $r \in \R_{> 0}$ be a (strictly) positive real number.
Let $x, y \in \Q$ be rational numbers.
Let $r^x$ be defined as $r$ to the power of $x$.
Then:
- $\paren {r^x}^y = r^{x y}$
Proof
Let $x = \dfrac p q, y = \dfrac u v$.
Consider $\paren {\paren {r^x}^y}^{q v}$.
Then:
\(\ds \paren {\paren {r^x}^y}^{q v}\) | \(=\) | \(\ds \paren {\paren {r^\paren {p / q} }^\paren {u / v} }^{q v}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \paren {\paren {\paren {r^\paren {p / q} }^\paren {u / v} }^v}^q\) | Product of Indices of Real Number: Integers | |||||||||||
\(\ds \) | \(=\) | \(\ds \paren {\paren {r^\paren {p / q} }^u}^q\) | Definition of Rational Power | |||||||||||
\(\ds \) | \(=\) | \(\ds \paren {r^\paren {p / q} }^{q u}\) | Product of Indices of Real Number: Integers | |||||||||||
\(\ds \) | \(=\) | \(\ds \paren {\paren {r^\paren {p / q} }^q}^u\) | Product of Indices of Real Number: Integers | |||||||||||
\(\ds \) | \(=\) | \(\ds \paren {r^p}^u\) | Definition of Rational Power | |||||||||||
\(\ds \) | \(=\) | \(\ds r^{p u}\) | Product of Indices of Real Number: Integers | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds \paren {\paren {r^\paren {p / q} }^\paren {u / v} }\) | \(=\) | \(\ds r^{\paren {p u} / \paren {q v} }\) | taking $q v$th root of both sides | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds \paren {r^x}^y\) | \(=\) | \(\ds r^{x y}\) |
$\blacksquare$
Sources
- 1977: K.G. Binmore: Mathematical Analysis: A Straightforward Approach ... (previous) ... (next): $\S 1$: Real Numbers: Exercise $\S 1.12 \ (3) \, \text{(ii)}$
- 1997: Donald E. Knuth: The Art of Computer Programming: Volume 1: Fundamental Algorithms (3rd ed.) ... (previous) ... (next): $\S 1.2.2$: Numbers, Powers, and Logarithms: Exercise $9$