Properties of Norm on Division Ring/Norm of Unity

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Theorem

Let $\struct {R, +, \circ}$ be a division ring with unity $1_R$.

Let $\norm {\,\cdot\,}$ be a norm on $R$.


Then:

$\norm {1_R} = 1$.


Proof

By Norm Axiom $\text N 2$: Multiplicativity:

$\forall x, y \in R: \norm {x \circ y} = \norm x \norm y$


In particular:

$\norm {1_R} = \norm {1_R \circ 1_R} = \norm {1_R} \norm {1_R}$


By Norm Axiom $\text N 1$: Positive Definiteness:

$\norm {1_R} \ne 0$


So $\norm {1_R}$ has an inverse in $R$.

Multiplying by this inverse:

$\norm {1_R} \norm {1_R} = \norm {1_R} \iff \norm {1_R} = 1$

as desired.

$\blacksquare$


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