Quasicomponents and Arc Components are Equal in Locally Arc-Connected Space
Jump to navigation
Jump to search
Theorem
Let $T = \struct {S, \tau}$ be a topological space which is locally arc-connected.
Then $A \subseteq S$ is an arc component of $T$ if and only if $A$ is a quasicomponent of $T$.
Proof
This theorem requires a proof. You can help $\mathsf{Pr} \infty \mathsf{fWiki}$ by crafting such a proof. To discuss this page in more detail, feel free to use the talk page. When this work has been completed, you may remove this instance of {{ProofWanted}} from the code.If you would welcome a second opinion as to whether your work is correct, add a call to {{Proofread}} the page. |
Sources
- 1978: Lynn Arthur Steen and J. Arthur Seebach, Jr.: Counterexamples in Topology (2nd ed.) ... (previous) ... (next): Part $\text I$: Basic Definitions: Section $4$: Connectedness