Radiocarbon Dating/Example/7000 BCE
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Example of Radiocarbon Dating
It was reported in the newspaper that a prehistoric village had been dated using radiocarbon dating.
The carbon-$14$ test had been used to measure the amount of radioactivity still present in the organic material found in the ruins.
It was determined that a settlement existed in that place as long ago as $\text {7000 BCE}$.
Given that:
- the estimated half-life of carbon-$14$ used was $5600$ years
- the newspaper report dated from about $1960$
the carbon-$14$ test must have shown that approximately $32 \%$ or $33 \%$ of carbon-$14$ was still present in the organic material at the time of discovery.
Proof
From First-Order Reaction, we have:
- $x = x_0 e^{-k t}$
where:
- $x$ is the quantity of carbon-$14$ at time $t$
- $x_0$ is the quantity of carbon-$14$ at time $t = 0$
- $k$ is a positive number.
By definition of half-life, when $x = \dfrac {x_0} 2$, we have $t = 5600$.
So:
- $e^{-5600 k} = \dfrac 1 2$
So:
- $k = \dfrac {\ln 0.5} {-5600} = \dfrac {\ln 2} {5600}$
After $7000 + 1960$ years:
\(\ds \dfrac x {x_0}\) | \(=\) | \(\ds e^{-8960 \paren {\ln 2 / 5600} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 0.3299\) |
So there is between $32 \%$ and $33 \%$ remaining.
$\blacksquare$
Sources
- 1963: Morris Tenenbaum and Harry Pollard: Ordinary Differential Equations ... (previous) ... (next): Chapter $1$: Basic Concepts: Lesson $1$: How Differential Equations Originate: Exercise $1.3$