Real Number Ordering is Compatible with Multiplication/Positive Factor

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Theorem

$\forall a, b, c \in \R: a < b \land c > 0 \implies a c < b c$


where $\R$ is the set of real numbers.


Corollary

$\forall a, b, c, d \in \R: 0 < a < b \land 0 < c < d \implies a c < b d$


Proof

From Real Numbers form Ordered Integral Domain, $\struct {\R, +, \times, \le}$ forms an ordered integral domain.

Thus:

\(\ds a\) \(<\) \(\ds b\)
\(\ds \leadsto \ \ \) \(\ds b - a\) \(>\) \(\ds 0\) Definition of Positivity Property
\(\ds \leadsto \ \ \) \(\ds c \times \paren {b - a}\) \(>\) \(\ds 0\) Definition 1 of Ordered Integral Domain: $(\text P 1)$: Closure under Ring Addition
\(\ds \leadsto \ \ \) \(\ds b \times c - a \times c\) \(>\) \(\ds 0\) Ring Axiom $\text D$: Distributivity of Product over Addition
\(\ds \leadsto \ \ \) \(\ds a \times c\) \(<\) \(\ds b \times c\) Definition of Positivity Property

$\blacksquare$


Examples

$15 \times 3$ Greater than $12 \times 3$

We have that:

$15 > 12$

so by Real Number Ordering is Compatible with Multiplication:

$15 \times 3 > 12 \times 3$

That is:

$45 > 36$


$\dfrac {15} 3$ Greater than $\dfrac {12} 3$

We have that:

$15 > 12$

so by Real Number Ordering is Compatible with Multiplication:

$\dfrac {15} 3 > \dfrac {12} 3$

That is:

$5 > 4$


$15 \times \paren {-3}$ Less than $12 \times \paren {-3}$

We have that:

$15 > 12$

so by Real Number Ordering is Compatible with Multiplication:

$15 \times \paren {-3} < 12 \times \paren {-3}$

That is:

$-45 < -36$


$\dfrac {15} {-3}$ Less than $\dfrac {12} {-3}$

We have that:

$15 > 12$

so by Real Number Ordering is Compatible with Multiplication:

$\dfrac {15} {-3} < \dfrac {12} {-3}$

That is:

$-5 < -4$


Sources

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