Secant of 150 Degrees
Jump to navigation
Jump to search
Theorem
- $\sec 150 \degrees = \sec \dfrac {5 \pi} 6 = -\dfrac {2 \sqrt 3} 3$
where $\sec$ denotes secant.
Proof
\(\ds \sec 150 \degrees\) | \(=\) | \(\ds \map \sec {90 \degrees + 60 \degrees}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds -\csc 60 \degrees\) | Secant of Angle plus Right Angle | |||||||||||
\(\ds \) | \(=\) | \(\ds -\dfrac {2 \sqrt 3} 3\) | Cosecant of $60 \degrees$ |
$\blacksquare$
Sources
- 1968: Murray R. Spiegel: Mathematical Handbook of Formulas and Tables ... (previous) ... (next): $\S 5$: Trigonometric Functions: Exact Values for Trigonometric Functions of Various Angles