Set is Subset of Union/Family of Sets/Proof 1

From ProofWiki
Jump to navigation Jump to search


Let $\family {S_\alpha}_{\alpha \mathop \in I}$ be a family of sets indexed by $I$.


$\ds \forall \beta \in I: S_\beta \subseteq \bigcup_{\alpha \mathop \in I} S_\alpha$

where $\ds \bigcup_{\alpha \mathop \in I} S_\alpha$ is the union of $\family {S_\alpha}$.


Let $x \in S_\beta$ for some $\beta \in I$.


\(\ds x\) \(\in\) \(\ds S_\beta\)
\(\ds \leadsto \ \ \) \(\ds x\) \(\in\) \(\ds \set {x: \exists \alpha \in I: x \in S_\alpha}\) Definition of Indexed Family of Sets
\(\ds \leadsto \ \ \) \(\ds x\) \(\in\) \(\ds \bigcup_{\alpha \mathop \in I} S_\alpha\) Definition of Union of Family
\(\ds \leadsto \ \ \) \(\ds S_\beta\) \(\subseteq\) \(\ds \bigcup_{\alpha \mathop \in I} S_\alpha\) Definition of Subset

As $\beta$ was arbitrary, it follows that:

$\ds \forall \beta \in I: S_\beta \subseteq \bigcup_{\alpha \mathop \in I} S_\alpha$