Set of Finite Subsets of Countable Set is Countable/Proof 1
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Theorem
Let $A$ be a countable set.
Then the set of finite subsets of $A$ is countable.
Proof
By the definition of a countable set, there exists an injection $g: A \to \N$.
Let $\FF$ denote the set of all finite subsets of $A$.
Let $f: \FF \to \N$ be the mapping defined by:
- $\ds \map f F = \prod_{k \mathop \in \map g F} p_{k + 1}$
where $p_n$ denotes the $n$th prime number.
We define $\map f \O = 1$, the vacuous product.
Let $F, G \in \FF$, and suppose that $\map f F = \map f G$.
By Expression for Integer as Product of Primes is Unique:
- $\map g F = \map g G$
By Subset equals Preimage of Image iff Mapping is Injection:
- $F = \map {g^{-1} } {\map g F} = \map {g^{-1} } {\map g G} = G$
That is, $f$ is an injection.
$\blacksquare$