Sigma-Algebra Contains Generated Sigma-Algebra of Subset

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Theorem

Let $\sigma_\FF$ be a be a $\sigma$-algebra on a set $\FF$.

Let $\sigma_\FF$ contain a set of sets $\EE$.

Let $\map \sigma \EE$ be the $\sigma$-algebra generated by $\EE$.


Then $\map \sigma \EE \subseteq \sigma_\FF$


Proof

$\sigma_\FF$ is a $\sigma$-algebra containing $\EE$.

$\map \sigma \EE$ is a subset of all $\sigma$-algebras containing $\FF$, by definition of a generated $\sigma$-algebra.

Therefore it contains $\map \sigma \EE$.

$\blacksquare$


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