# Sine Function is Odd

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## Theorem

For all $z \in \C$:

$\map \sin {-z} = -\sin z$

That is, the sine function is odd.

## Proof

Recall the definition of the sine function:

 $\displaystyle \sin z$ $=$ $\displaystyle \sum_{n \mathop = 0}^\infty \paren {-1}^n \frac {z^{2 n + 1} } {\paren {2 n + 1}!}$ $\displaystyle$ $=$ $\displaystyle z - \frac {z^3} {3!} + \frac {z^5} {5!} - \cdots$

From Sign of Odd Power, we have that:

$\forall n \in \N: -\paren {z^{2 n + 1} } = \paren {-z}^{2 n + 1}$

The result follows directly.

$\blacksquare$