Sine of Three Right Angles less Angle

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Theorem

$\map \sin {\dfrac {3 \pi} 2 - \theta} = -\cos \theta$

where $\sin$ and $\cos$ are sine and cosine respectively.


Proof

\(\ds \map \sin {\frac {3 \pi} 2 - \theta}\) \(=\) \(\ds \sin \frac {3 \pi} 2 \cos \theta - \cos \frac {3 \pi} 2 \sin \theta\) Sine of Difference
\(\ds \) \(=\) \(\ds \paren {-1} \times \cos \theta - 0 \times \sin \theta\) Sine of Three Right Angles and Cosine of Three Right Angles
\(\ds \) \(=\) \(\ds -\cos \theta\)

$\blacksquare$


Also see


Sources