Star Convex Set is Simply Connected
Theorem
Let $A$ be a star convex subset of a topological vector space $\struct {V, \tau}$ over $\R$ or $\C$.
Let $\tau_A$ be the subspace topology on $A$ induced by $\tau$.
Then $\struct{ A, \tau_A }$ is simply connected.
Proof
Let $a \in A$ be a star center of $A$.
Define $\mathbb I := \closedint 0 1$ as a closed real interval.
Let $\gamma : \mathbb I \to A$ be a loop in $A$ with base point $a$.
Let $\sigma : \mathbb I \to \set a$ be the constant function.
Constant Function is Continuous shows that $\sigma$ is continuous, so $\sigma$ is a loop with base point $a$.
Define $H: \mathbb I \times \mathbb I \to A$ by:
- $\map H { s, t } = t \map {\gamma} s + \paren { 1-t } a$
By definition of star convex set, we have $\map H { s, t } \in A$ for all $\tuple { s, t } \in \mathbb I \times \mathbb I$.
Define $F : \mathbb I \times \mathbb I \to A \times \mathbb I$ by $ \map F { s, t } = \tuple { \map { \gamma }{ s } , t }$.
As a loop is continuous, it follows that $F$ is continuous.
Define $\tilde G : V \times \mathbb I \to V$ by $\map { \tilde G }{ v, t } = t v + \paren { 1-t } a$.
By definition of topological vector space, it follows that $\tilde G$ is continuous.
Let $G = \tilde G {\restriction_{\paren {A \times \mathbb I} \times A} }$ be the restriction of $\tilde G$ to $\paren {A \times \mathbb I} \times A$.
Restriction of Continuous Mapping is Continuous:Topological Spaces shows that $G$ is continuous.
Composite of Continuous Mappings is Continuous shows that $ H = G \circ F$ is continuous.
For all $s, t \in \mathbb I$, we check that $H$ is a path homotopy between $\gamma$ and $\sigma$:
\(\ds \map H { s, 0 }\) | \(=\) | \(\ds a\) | \(\ds = \: \map { \sigma } s\) | |||||||||||
\(\ds \map H { s, 1 }\) | \(=\) | \(\ds \map { \gamma } s\) | ||||||||||||
\(\ds \map H { 0, t }\) | \(=\) | \(\ds ta + \paren { 1-t } a\) | \(\ds = \: a\) | |||||||||||
\(\ds \map H { 1, t }\) | \(=\) | \(\ds ta + \paren { 1-t } a\) | \(\ds = \: a\) |
It follows that all loops with base point $a$ are path-homotopic with $\sigma$.
Relative Homotopy is Equivalence Relation shows that all loops with base point $a$ are path-homotopic with each other.
This implies that the fundamental group $\map { \pi_1 } { A, a }$ is trivial.
Star Convex Set is Path-Connected shows that $A$ is path-connected.
Hence the result.
$\blacksquare$
Sources
- 2000: James R. Munkres: Topology (2nd ed.): $9$: The Fundamental Group: $\S 52$: The Fundamental Group